f(x+1)=x^2+5x-1

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Solution for f(x+1)=x^2+5x-1 equation:


Simplifying
f(x + 1) = x2 + 5x + -1

Reorder the terms:
f(1 + x) = x2 + 5x + -1
(1 * f + x * f) = x2 + 5x + -1
(1f + fx) = x2 + 5x + -1

Reorder the terms:
1f + fx = -1 + 5x + x2

Solving
1f + fx = -1 + 5x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
1 + 1f + fx + -5x + -1x2 = -1 + 5x + x2 + 1 + -5x + -1x2

Reorder the terms:
1 + 1f + fx + -5x + -1x2 = -1 + 1 + 5x + -5x + x2 + -1x2

Combine like terms: -1 + 1 = 0
1 + 1f + fx + -5x + -1x2 = 0 + 5x + -5x + x2 + -1x2
1 + 1f + fx + -5x + -1x2 = 5x + -5x + x2 + -1x2

Combine like terms: 5x + -5x = 0
1 + 1f + fx + -5x + -1x2 = 0 + x2 + -1x2
1 + 1f + fx + -5x + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
1 + 1f + fx + -5x + -1x2 = 0

The solution to this equation could not be determined.

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